Question

Mother is 25 year older than her son. Find son’s age if after 8 years ratio of son’s age to mother’s age will be 4/9.

Answer 1

Heya !!



Let present age of son be X years.



Age of mother = ( X + 25 ) years.






After 8 years age of son= ( X + 8 ) years.



After 8 years age of mother = ( X + 25 + 8 ) = ( X + 33 ) years.




According to the question,




X+ 8 / X + 33 = 4/9




9 ( X + 8 ) = 4 ( X + 33 )



9X + 72 = 4X + 132





9X - 4X = 132 - 72



5X = 60



X = 60/5



X = 12 years.



Present age of son = X = 12 Years.



And,


Present age of mother = X + 25 = 12 + 25 = 37 years.

Answer 2

Hey!!

Let the present age of son be x year

the present age of mother be ( x + 25 ) years

After 8 years of son = ( x + 8 ) years

After 8 years of mother = ( x + 25 + 8 ) = ( x + 33 ) years

A / q

( x + 8 ) / ( x + 33 ) = 4 / 9

=> 9 ( x + 8 ) = 4 ( x + 33 )

=> 9x + 72 = 4x + 132

=> 9x - 4x = 132 - 72

=> 5x = 60

=> x = 60 / 5

=> x = 12 years

Present age of son = x = 12 years

Present age of mother = ( x + 25 ) = 12 + 25 = 37 years


Hope it will helps you ✌