Question

mother is 25 years olden than her son. Find son's age if after 8years ratio of son's age to mother's age will be 4 upon 9.​

Answer 1

Answer:

Step-by-step explanation:

Let the present age of son be x year

the present age of mother be ( x + 25 ) years

After 8 years of son = ( x + 8 ) years

After 8 years of mother = ( x + 25 + 8 ) = ( x + 33 ) years

A / q

( x + 8 ) / ( x + 33 ) = 4 / 9

=> 9 ( x + 8 ) = 4 ( x + 33 )

=> 9x + 72 = 4x + 132

=> 9x - 4x = 132 - 72

=> 5x = 60

=> x = 60 / 5

=> x = 12 years

Present age of son = x = 12 years

Present age of mother = ( x + 25 ) = 12 + 25 = 37 years

Hope it will helps you ✌

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Answer 2

the given

mother is 25 years olden than her son

let be mother age =X

and son age =y

according the question

25y=X -------------(|)

and second equation is

after 8year son and mother age ratio is 4upon 9

(X+8)/(Y+8)=4/9

X+8/y+8=4/9

crows into

9x+72=4y+32

9x-4y=32-72

9x-4y=-40 -----------(||)

equation first put on equation second

9×(25y)-4y=-40

225y-4y=-40

221y=-40

y=-40/221

I hope this answer is right