Math, asked by tanish98, 1 year ago

mother is 25 years older than her son find son's if after 8 years ratio of son's age mother 's age will be 4upon 9

Answers

Answered by Meenal23
8
Let son of the age be X years.

Mother's age = X + 25 years

After 8 years,

Son's age = X + 8 years

Mother's age = X + 25 + 8 = X + 33 years

Given,

Son's age : mother's age = 4:9

(X+8):(X+33) = 4:9

(X+8)/(X+33) = 4/9

9(X+8) = 4(X+33)

9X + 72 = 4X + 132

9X - 4X = 132 - 72

5X = 60

X = 12

Thus, son's age is 12 years

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punamshinde: right answers
Answered by sanjeevgupta84
4

Let son's age be x.

Mother's age = x+25

After 8 years,

Sons age = x+8 and

mother's age = x+25+8 =x+33

Ratio of son's and mother's age = 4:9

x+8/x+33 =4/9

9(x+8)=4(x+33)

9x+72=4x+132

9x-4x=132-72

5x=60

x=12

Therefore, son's age =12 years and mother's age =x+25=12+25=37 years

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