mother is 25 years older than her son find son's if after 8 years ratio of son's age mother 's age will be 4upon 9
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Let son of the age be X years.
Mother's age = X + 25 years
After 8 years,
Son's age = X + 8 years
Mother's age = X + 25 + 8 = X + 33 years
Given,
Son's age : mother's age = 4:9
(X+8):(X+33) = 4:9
(X+8)/(X+33) = 4/9
9(X+8) = 4(X+33)
9X + 72 = 4X + 132
9X - 4X = 132 - 72
5X = 60
X = 12
Thus, son's age is 12 years
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Mother's age = X + 25 years
After 8 years,
Son's age = X + 8 years
Mother's age = X + 25 + 8 = X + 33 years
Given,
Son's age : mother's age = 4:9
(X+8):(X+33) = 4:9
(X+8)/(X+33) = 4/9
9(X+8) = 4(X+33)
9X + 72 = 4X + 132
9X - 4X = 132 - 72
5X = 60
X = 12
Thus, son's age is 12 years
Hope it helps :)
Pls mark as brainliest :)
punamshinde:
right answers
Answered by
4
Let son's age be x.
Mother's age = x+25
After 8 years,
Sons age = x+8 and
mother's age = x+25+8 =x+33
Ratio of son's and mother's age = 4:9
x+8/x+33 =4/9
9(x+8)=4(x+33)
9x+72=4x+132
9x-4x=132-72
5x=60
x=12
Therefore, son's age =12 years and mother's age =x+25=12+25=37 years
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