Math, asked by monalisachakrab2439, 8 months ago

Mother is 25 years older than her son. Find sons age if after 8 years ratio of son's age to mother's age will be 4_9

Answers

Answered by sanjeevk28012
10

Answer:

The Age of Son's after 8 years is 12 years .

Step-by-step explanation:

Given as :

Age of mother = 25 years + Age of son

Let The age of son = S years

Let The age of mother = M years

So, M = 25 + S           .......1

Again

After 8 years, Age of mother = M + 8 years

After 8 years, age of son = S + 8 years

And

After 8 years ratio of son's age to mother's age will be 4 : 9

i.e \dfrac{S+8}{M+8}  = \dfrac{4}{9}

Or, 9 S + 72 = 4 M + 32                   .......2

From eq 1  

9 S + 72 = 4 ( 25 + S ) + 32

Or, 9 S + 72 = 100 + 4 S + 32

Or, 9 S - 4 S = 132 - 72

Or, 5 S = 60

∴   S = \dfrac{60}{5}

i.e  S= 12 years

So, The Age of son = S = 12 years

Put the value of S in eq 1

i.e  M = 25 + S

Or, M = 25 + 12 = 37 years

So, The Age of mother = M = 37 years

Hence, The Age of Son's after 8 years is 12 years . Answer

Answered by raufnpatel
0

Answer:

12 years

Step-by-step explanation:

Let sons age be x years

Mother age will be x + 25

by the given condition,

After 8 years sons age will be x+8

After 8 years mothers age will be x+5+8= x+33

x+8 / x+33= 4/9

9(x+8)= 4(x+33)

9x+72= 4x+132

9x-4x= 132-72

5x=60

x=60/8

=12 years

Answer: Sons age will be 12 years old ..

Similar questions