mother's age is 12 years more than twice her son's age. after 8 years mother's age will be 20 years less than three times her son's age. find their age.
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2x +12=mom age,son age =x
Ata
2x+12+8=3x-20
X=40 yrs
Mom age =92
Ata
2x+12+8=3x-20
X=40 yrs
Mom age =92
Answered by
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Let present age of her son be 'x' years
mother's age is 12 years more than twice her son's age
and her mother's present age = 2x + 12
After 8 years,
son's age = x + 8
mother's age = 2x + 12 + 8 = 2x + 20
mother's age will be 20 years less than three times her son's age.
2x + 20 = 3(x + 8) - 20
2x + 20 + 20 = 3x + 24
2x + 40 = 3x + 24
3x - 2x = 40 - 24
x = 16
Son's present age = 16 years
his mother's present age = 2(16) + 12
= 32 + 12
= 44 years
mother's age is 12 years more than twice her son's age
and her mother's present age = 2x + 12
After 8 years,
son's age = x + 8
mother's age = 2x + 12 + 8 = 2x + 20
mother's age will be 20 years less than three times her son's age.
2x + 20 = 3(x + 8) - 20
2x + 20 + 20 = 3x + 24
2x + 40 = 3x + 24
3x - 2x = 40 - 24
x = 16
Son's present age = 16 years
his mother's present age = 2(16) + 12
= 32 + 12
= 44 years
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