Question

Mother's age is 8 yrs more than twice her daughter's age. The sum of mother's age & daughter's age is 56 yrs. Take daughter's age as x.

Answer 1

Step-by-step explanation:

$\large \red{ \boxed{ \blue{ \boxed{ \green {given}}}}}$

Daughter present age=x yrs

Mothers present age=2x+8 yrs

$\large \blue{ \boxed{ \pink{ \boxed{ \green {according \: to \: question}}}}}$

• x+2x+8=56
• 3x+8=56
• 3x=56-8
• x=48/3=16

$\huge \orange{ \boxed{ \blue{ \boxed{ \green {daughter \: present \: age =16 yrs \:and \: mother \: present \: age =32+8=40yrs}}}}}$

Answer 2

Answer: x=16

Step-by-step explanation: