Question

MOTIC
m in first 2s
Q.11. An electron moving with a
5 x 104 ms- enters into a uniform electric field
and acquires a uniform acceleration of 104
acquire a velocity double of its initial velocity
(b) How much distance the electron would cover
Va = (8-4)
= -1 ms!
the velocity
For the last six seonds
(a) Calculate the time in which the electron would
For the next four seconds.
(4-4)
= 0 ms-1
0-6
V.
16-10
in the direction of its initial motion.
Q.13
(OV
velocity of
ms
52
An
é
в с
Ans. (a)
3s, a = ?
in this time?
u = 5 x 104m s-1
v = 2 x (5 x 104)
= 10 x 104
1 = ?, a = 104 m 5-2
ms!
V=U + at
10 x 104 = 5 x 10+4 x 104t
(10 - 5)104 = 104 = t = 5s
1
-?v=?
(b)
S = ut +
2
1
acement
211416
s = (5 x 104 x 5) + x (104) (5,-
2
$ = 37.5 x 104m.
Q.12. Obtain a relation for the distance travelled by an
object moving with a uniform acceleration in the
interval between 4th and 5th seconds.
3210
First 4s,
Ans. O to A
1
Suf +
at2​

Answer 1

Answer:

it is defecult to answer

Explanation:

from next time make the questions esy. so that normal people can also ans it