Question

Motion of a particle is given by equation
s = (3t3+ 7t2 + 14t + 8) m
The value of acceleration of the particle at
(1) 10 m/s2
(2) 32 m/s2
(4) 16 m/s2
-3) 23 m/s2​

Answer 1

Answer:

32 m/s^2

Explanation:

from given equation,

double differetiation is 18t+14

Now put the value of time t

t=1

you will get the answer

=18×1 + 14

=32 m/s^2

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