Physics, asked by dhanpalsingh2004, 11 months ago

motion of inertia of ring passes from diameter​

Answers

Answered by sharansai42
1

By the law of perpendicular axes the sum of moments of inertia of a ring about two mutually perpendicular diameters is mr^2. So the diameters being symmetric moment of inertia about each Axis is 1/2mr^2. ... So moment about a tangent is 3/2mr^2.

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