Motion of rod of length l but centre of mass at l/3
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Answer:
12ML2
Explanation:

The moment of inertia of a single rod about an axis passing through its center and perpendicular to it is
112ML2
That of each side of the equilateral triangle about an axis passing through the triangle's center and perpendicular to its plane is
112ML2+M(L2√3)2=16ML2
(by the parallel axis theorem).
The moment of inertia of the triangle about this axis is then
3×16ML2=12ML2
12ML2
Explanation:

The moment of inertia of a single rod about an axis passing through its center and perpendicular to it is
112ML2
That of each side of the equilateral triangle about an axis passing through the triangle's center and perpendicular to its plane is
112ML2+M(L2√3)2=16ML2
(by the parallel axis theorem).
The moment of inertia of the triangle about this axis is then
3×16ML2=12ML2
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