motorbike is running at a velocity of 72 km/h. On applying brakes, it is brought to rest in 2 s. What is the distance covered by the motorbike before coming to rest?
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A motorbike initially at rest, picks up a velocity of 72km/h
−1
over a distance of 40m. Calculate (1)acceleration (2)time in which it picks up above velocity
u=0
v=72km/m=72×
18
5
=20m/s
v
2
=u
2
+2as
20×20=0+2×40×a
a=5m/s
2
v=u+at
20−0=at
t=4sec
−1
over a distance of 40m. Calculate (1)acceleration (2)time in which it picks up above velocity
u=0
v=72km/m=72×
18
5
=20m/s
v
2
=u
2
+2as
20×20=0+2×40×a
a=5m/s
2
v=u+at
20−0=at
t=4sec
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