Question

motorbike is travelling with a velocity of 3 and -1 it is accelerated it accelerates at the rate of 9.3 m s -2 for 1.8 second calculate the distance travelled in the in this time​

Answer 1

❍ Given that, motorbike is travelling with a velocity of 3 m/s and it accelerates at the rate of 9.3 m/s² for 1.8 seconds.

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To calculate the distance travelled in this time we have to apply the second equation of motion :

 $\bigstar \; \; {\large{\underline{\boxed{\bf s=ut + \dfrac{1}{2}at^{2}}}}$

•  s denotes distance travelled

•  u denotes initial velocity

•  a denotes acceleration

•  t denotes time

$\sf : \; \implies s = [ \; 3 \times 1.8 \; ] + \dfrac{1}{2} \times 9.3 \times [ \; 1.8 \times 1.8 \;]$

$\sf : \; \implies s =[ \; 3 \times 1.8 \; ] + \dfrac{1}{2} \times 9.3 \times [ \; 3.24 \;]$

$\sf : \; \implies s = [ \; 3 \times 1.8 \; ] + \dfrac{1}{2} \times \dfrac{93}{10} \times \dfrac{324}{100}$

$\sf : \; \implies s = [ \; 3 \times \dfrac{18}{10} \; ] + \dfrac{93}{10} \times \dfrac{162}{100}$

$\sf : \; \implies s = \dfrac{54}{10} + \dfrac{15066}{1000}$

$\sf : \; \implies s = 5.4 + 15.066$

$\sf : \; \implies s = 20.466 \; m$

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•  Henceforth, the motorbike travels approx. distance of 20.4 m

Answer 2

Explanation:

I hope this is help full to you