motorbike running at 5 M per second pick up velocity of 30 M per second in 5second calculate acceleration and distance covered during acceleration
Answers
Answered by
30
Hey there, here is your solution
_______________________________
Acceleration= V - U / t
= 30 - 5 /5
= 25/5 = 5 m/s^2 Ans.
________________________________
V^2 - U^2 / 2a = distance
distance = (30)^2-(5)^2/2*5
=900-25/10
=875/10=87.5m Ans.
_______________________________
Acceleration= V - U / t
= 30 - 5 /5
= 25/5 = 5 m/s^2 Ans.
________________________________
V^2 - U^2 / 2a = distance
distance = (30)^2-(5)^2/2*5
=900-25/10
=875/10=87.5m Ans.
sheikhAbhishek:
the unit of acclaration is m/s^2
Answered by
8
acclaration =final velocity - initial velocity÷time
a = 30-5 and then divided by 5
a = 25÷5
acclaration= 5m/s2
a = 30-5 and then divided by 5
a = 25÷5
acclaration= 5m/s2
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