Math, asked by hdik, 6 months ago


Motorcycle is bought at rupees 160000 . Its value depreciates at the rate of 10% per annum find its value after
i ) 1 years ?
ii ) 2 years ?​

Answers

Answered by ManasviPatankar
17

Answer:

Value after 1 year = Rs 144000

Value after 2 years = Rs 129600

Step-by-step explanation:

Principle - 160000

Rate of principle - 10%

value after 1 year - ?

=Rs {160000 × ( 1 - 10/100 )}

=Rs {160000 × 9/10}

=Rs 144000

Therefore, after 1 year the value will be Rs 144000.

value after 2 years - ?

=Rs {160000 × ( 1 - 10/100 )²}

=Rs {160000 × 9/10 × 9/10}

=Rs 129600

Therefore, value after 2 years will be Rs 129600.

Answered by qwcasillas
3

Given,

The cost of the Motorcycle is Rs.160000 and depreciation is 10% per annum.

To Find,

Value of the Motorcycle at the end of 1st year and 2nd year.

Solution,

Depreciation per year = 10%

Cost of the Motorcycle = Rs.160000

The Value of Depreciation for the 1st year = 160000×\frac{10}{100} = 16000

Thus the value of the Motorcycle at the end of 1st year = 160000 - 16000 = 144000

Similarly depreciation for the 2nd year = 144000×\frac{10}{100} = 14400

Thus the value of the Motorcycle at the end of 2nd year = 144000 - 14400

= 129600

Henceforth the value of the motorcycle after 1 year is Rs.144000 and after 2 years is Rs.129600

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