Question

motorcycle is moving with a velocity of 90 kilometre per hour and it takes 5 second to stop after the brakes are applied. (1):find fotce if mass is 200kg. (2):find distance by second law​

Answer 1

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u=90km/h

90*(5/18)

u=25m/s

u=25m/st=5sec

u=25m/st=5seca=?

u=25m/st=5seca=?v=0m/s

v=u+at

0=25+a(5)

-25/5=a

a=-5m/s²

i)

for force

F=ma

F=200*5

=1000N

ii) s=ut+(1/2)at²

s=25*5+(1/2)(-5)(5²)

s=125-125/2

s=250-125/2

s=125/2

s=62.5m

Hope it Helps

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