Physics, asked by manavrathore8698, 9 months ago

Motorcycle moving with a speed of 5 metre per second is subjected to an acceleration 0.2 metre per second square calculate the speed of motorcycle after 11 and the distance travelled in this time

Answers

Answered by AaminAftab21
3

u = 5ms {}^{ - 1}

a = 0.2ms {}^{ - 2}

t = 11 \: sec

\large{s = ut +  \frac{1}{2} at {}^{2}}

\large{s = 5 \times 11 +  \frac{1}{2} 0.2 \times 11 \times 11}

\large{s = 55 +  \frac{1}{2}  \times 0.2 \times 121}

\large{s = 55 + 12.1}

\huge\orange{\boxed{s = 67.1 \: meter}}

\large{speed =  \frac{distance}{time}}

\large{speed =  \frac{67.1 \: m}{11 \: sec}}

\huge\purple{\boxed{\underline{\orange{speed = 6.1ms {}^{ - 1}}}}}

\large\red{\underline{\underline{\mathbb{MARK\:AS\:BRAINLIEST}}}}

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