Question

motorcycle running due West at a velocity of 72 kilometre per hour is brought to rest in 2 seconds by the application of brakes distance covered by the motorcycle in these 2 second is​

Answer 1

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Answer 2

The distance covered by the motorcycle in these 2 second is 20 meters.

Explanation:

Given that,

Initial speed of the motorcycle, u = 72 km/h = 20 m/s

It brought to rest, v = 0

Time, t = 2 s

Let a is the acceleration of the motorcycle. It is given by the formula as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{0-20\ m/s}{2\ s}\\\\a=-10\ m/s^2$

Let d is the distance covered by the motorcycle in these 2 second. It can be calculated using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2\\\\d=20\times 2+\dfrac{1}{2}\times (-10)\times 2^2\\\\d=20\ m$

So, the distance covered by the motorcycle in these 2 second is 20 meters. Hence, this is the required solution.

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Kinematics

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