motorcyclist attends a velocity of 36 km/h alter accelerating uniformly from rest In 10 seconds. Find the distance travelled
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Answer:
We can calculate this question using the kinematic equations (SUVAT equations):
⇒Since in this question we have the initial velocity, from rest(u = 0 km/hr) and final velocity (v = 36km/hr) and time of 5 seconds, we will use the following kinematic equation:
S = 1/2 ( u + v) t
where S is the distance( displacement), u is the initial velocity ( 0 km/hr), v is the final velocity(36km/hr) and t is time taken(5 secs).
convert 36km/hr to m/s ⇒ 36km/hr × 10/36 = 10m/s
S = 1/2 ( 0 + 10) 5
S = 1/2 × 10 × 5
S = 5 × 5
S = 25 meters
Therefore the distance traveled by this car is 25 meters.
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