moves on straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance
of 40 m with an acceleration of 0.5 m/s2, work done by the man on the block during the motion is
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Answer:
•mass of a block = 2 kg
.acceleration of a block
= acceleration of a man
= 0.5 m/s^2 =
Displacement = 40 m
F=ma
F = 2x0.5
F=1N
Work Done = Force Displaceme
= 1x40
= 40 J =
Explanation:
Hope it helps you
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