moving at 32m/s slows uniformly to speed of 10 m/s in a time of 5 seconds derermine the distance moved in the third seconds
Answers
Answered by
3
Answer:
u=32m/s
v=10m/s
t=5sec
solution: a=(v-u)/t
a=(-12)/5
dist.= ut + 1/2at²
160 + (-30)
= 130m
Answered by
0
Answer:
Given; u= 32 m/s
v = 10m/s
t= 5 sec
d=?
a=(10m/s-32m/s) / 5sec
a= -20m/s/ 5 sec
a= -4 m/s
distance move after 3s- distance move after 2s
d= 72m-12m
d= 60m
Similar questions