Physics, asked by priyankackamble, 4 months ago

moving at 32m/s slows uniformly to speed of 10 m/s in a time of 5 seconds derermine the distance moved in the third seconds​

Answers

Answered by AbirAnokar
3

Answer:

u=32m/s

v=10m/s

t=5sec

solution: a=(v-u)/t

a=(-12)/5

dist.= ut + 1/2at²

160 + (-30)

= 130m

Answered by Linaxkho
0

Answer:

Given; u= 32 m/s

v = 10m/s

t= 5 sec

d=?

a=(10m/s-32m/s) / 5sec

a= -20m/s/ 5 sec

a= -4 m/s

distance move after 3s- distance move after 2s

d= 72m-12m

d= 60m

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