Question

moving at 6/5 of its usual speed a bus is 10 minutes too early find its usual time to cover the journey​

Answer 1

Answer:

Step-by-step explanation:

Let t1 be usual time

s1 be usual speed and s2 is speed

d be distance

t1=d/s1 let be equation 1

Given

s2= 6/5s1

t2= t1-10

t2=d/s2

t1-10=d/(6/5)*s1

From equation 1

t1-10 = (5/6)t1

t/6=10

t=60 minutes