Question

moving with uniform acceleration from the state of rest a body covers 22m during the 6th sec of its motion.what is the distance covered by it during the first 6thsec

Answer 1

We will use the following equation :

S = ut + 1/2at²

u= 0 since it begins from rest

In the 6th second :

t = 1

We can get a:

22 = 1/2 × a

a = 44 m / s²

When t= 6

S = 1/2 × 44 × 6² = 792 m

Answer :
. 792 m

Answer 2

Answer:

Explanation:

We will use the following equation :

S = ut + 1/2at²

u= 0 since it begins from rest

In the 6th second :

t = 1

We can get a:

22 = 1/2 × a

a = 44 m / s²

When t= 6

S = 1/2 × 44 × 6² = 792 m

Answer :

. 792 m