MP of an article is Rs. 1200. A shopkeeper give two
successive discount on MP. If one discount is 30 %n and selling
price of an article is Rs. 672. Find second discount %.
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1st discount is 30% then remaining value aftr 30%discount =1200×70/100=840
now ... let the 2nd discount is =y% and discount is (840-672)=168
according to question
840×y%=168
840×y/100=168
y=168×100/840
y=168×10/84
y=14×10/7
y=20%
or
when X and y are successive discount then .. equivalent discount is=(x+y)-xy/100
in this question equivalent
discount=(30+y)-30y/100
and we know that real discount is=1200-672= 528 .
in% =528×100/1200 = 44%
now, (30+y)-30y/100=44.
y=20%
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