Question

mple 1 For all n 2 1, prove that n(n+1) (2n +1) 12+22+ 32 +42 +...+ n2 6​

Answer 1

Answer:

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Solve : 12+22+32+...+n2=61n(n+1)(2n+1)

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Let p(n)=12+22+32+....+n2=6n(n+1)(2n+1)

for n=1

LHS=12=1

RHS=6(1)(1+1)(2×1+1)=61×2×3=1

LHS = RHS

P(n) is true for n=1

Assume that P(k) is true

12+22+32+...+k2=6k(k+1)(2k+1)

we will prove P(k+1) is true 

12+22+

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Answer 2

Answer:

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