Mr A invests a certain sum of money for 3 years at a simple interest rate of interest p.a. which fetches an interest of rs.225. Mr B invests the same sum o money for 2 years at a compound interest rate of interest which is equal to the rate at which Mr A invests. Mr B earns Rs. 153 by way of interest. Find the sum of money and the common rate of interest.
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Step-by-step explanation:
It is given that
SI for 3 years = 225
SI for 2 years = (225×2)/3=150
CI for 2 years = 153
So the difference = 153 - 150 = 3
Here 3 is interest on one year i.e. 75 for one year
We know that
Rate =(SI×100)/(P×t)
Substituting the values
=(3×100)/(75×1)
=4%
SI for 3 years = 225
Rate = 4% p.a.
So Principal = (SI×100)/(R×t)
Substituting the values
=(225×100)/(4×3)
=1875
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Answer:
1875 is the right answer
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