Question

mr. agarwal gave 45%of his monthly salary to his wife, spent 30% of salary and saved rest . If he saves ₹210 less than what he spent, how much money did he give to his wife​

Answer 1

Step-by-step explanation:

Step-by-step explanation

Since we have given that

Percentage of his monthly salary to his wife = 45%

Percentage of salary he spent = 30%

Percentage of salary he saved is given by

\begin{gathered}100-(30+45)\\\\=100-75\\\\=25\%\end{gathered}

100−(30+45)

=100−75

=25%

Let the monthly salary be 'x'.

According to question, we get that

\begin{gathered}0.45x-0.25x=210\\\\0.2x=210\\\\x=\dfrac{210}{0.2}\\\\x=1050\end{gathered}

0.45x−0.25x=210

0.2x=210

x=

0.2

210

x=1050

Hence, amount he gives to his wife is given by

\begin{gathered}0.45\times 1050\\\\=472.50\end{gathered}

0.45×1050

=472.50

Therefore, amount he gives to his wife is Rs. 472.50.

Answer 2

Answer:

Amount he gives to his

wife is Rs. 472.50 .

Step-by-step explanation:

Since we have given that

Percentage of his monthly salary to his

wife = 45%

Percentage of salary he spent =30%

Percentage of salary he saved is given by

=100-(30+45)\\\\=100-75\\\\=25\%\

=100-(30+45)

=100-75

=25%

Let the monthly salary be x

By the Problem,

0.45x - 0.25x = 210

0.2x =210

x = 210

–––

0.2

x = 1050

Hence , amount is give to his wife = 0.45 × 1050

= 472.50

Ans: Amount is give his wife is Rs. 472.50