Physics, asked by Tejapoosa9314, 1 year ago

Mr. akhilesh bajpai while going from luck now to jamshedpur covered half the distance by train at the speed of 96 km/hr, half the rest of the distance by his scooter at the speed of 60km/hr and the remaining distance at the aped of 40 km/hr by car. the average speed at which he completed his journey is:

Answers

Answered by nkhelwar
9
attachment is self explanatory
Attachments:
Answered by phillipinestest
7

"Total distance covered from Lucknow to Jamshedpur be ‘x’

Half the distance was covered by train means \frac { x }{ 2 } with the speed of 96Km/hr

Half the distance by the scooter ‘\frac { x }{ 4 }’ with the speed of 60Km/hr

Remaining distance ‘\frac { x }{ 4 }’ aped by car with 40Km/hr

Average speed = total distance/time taken

Average speed =\frac {x}{(\frac {x}{ \frac {2}{96}})+(\frac {x}{ \frac {4}{60}})+(\frac {x}{ \frac {4}{40}})}

By simplifying the above equation we get, 64Km/hr

The average speed at the he completed his journey is 64Km/hr"

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