Mr. Amrit decided to build a cylindrical shelter for orphans to a height of 3m and conical above it. If its diameter is 105 m and slant height of conical portion is 53 m , calculator the length of The canvas 5cm wide to make the shelter.What values are depicted in Mr. Amrit plan ?
Answers
Given:
Mr. Amrit decided to build a cylindrical shelter for orphans to a height of 3m and conical above it. If its diameter is 105 m and the slant height of the conical portion is 53 m
To find:
The length of The canvas 5cm wide to make the shelter. What values are depicted in Mr. Amrit plan?
Solution:
The height of the cylindrical part of the shelter, h = 3 m
The diameter of the base = 105 m
∴ The radius of the base, r =
The slant height of the conical portion, l = 53 m
So,
The required canvas to build the shelter for orphans is,
= [Curved surface area of the cylindrical part] + [Curved surface area of the conical part]
=
=
on substituting the given values of r, h and l, we get
=
=
=
Since the canvas used for the shelter is in the form of a rectangle, so let "l" and "w" be the length and width of that rectangular canvas.
Here the width of the canvas, w = 5 cm
∴ Length × Width = Area of the rectangular canvas
⇒ l × w = Area
on substituting the value of w = 5 m and Area = 9735 m², we get
⇒ l × 0.05 = 9735
⇒ l =
⇒ l = 194700 m
Thus, the length of the canvas 5 cm wide to make the shelter is →
194700 m.
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