Math, asked by jaskaransidhu9204, 1 month ago

Mr. Amrit decided to build a cylindrical shelter for orphans to a height of 3m and conical above it. If its diameter is 105 m and slant height of conical portion is 53 m , calculator the length of The canvas 5cm wide to make the shelter.What values are depicted in Mr. Amrit plan ?​

Answers

Answered by bhagyashreechowdhury
0

Given:

Mr. Amrit decided to build a cylindrical shelter for orphans to a height of 3m and conical above it. If its diameter is 105 m and the slant height of the conical portion is 53 m  

To find:

The length of The canvas 5cm wide to make the shelter. What values are depicted in Mr. Amrit plan?​

Solution:

The height of the cylindrical part of the shelter, h = 3 m

The diameter of the base = 105 m

∴ The radius of the base, r = \frac{105}{2} = 52.5 \: m

The slant height of the conical portion, l = 53 m

So,

The required canvas to build the shelter for orphans is,

= [Curved surface area of the cylindrical part] + [Curved surface area of the conical part]

= 2 \pi r h + \pi rl

= \pi r [2h + l]

on substituting the given values of r, h and l, we get

= \frac{22}{7} \times 52.5 \times [(2\times 3) + 53]

= \frac{22}{7} \times 52.5 \times 59

= \bold{9735\:m^2}

Since the canvas used for the shelter is in the form of a rectangle, so let "l" and "w" be the length and width of that rectangular canvas.

Here the width of the canvas, w = 5 cm

∴ Length × Width = Area of the rectangular canvas

⇒ l × w = Area

on substituting the value of w = 5 m and Area = 9735 m², we get

⇒ l × 0.05 = 9735

⇒ l = \frac{9735}{0.05}

l = 194700 m

Thus, the length of the canvas 5 cm wide to make the shelter is →

194700 m.

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