Math, asked by sohailsk40, 1 year ago

Mr chaudhary invests Rs 20,800 in 6% Rs 100 shares at Rs 104, and Rs 14,300 in 10.5% Rs 100 shares at Rs 143. What will be his annual income from the shares ?

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Answered by bhagyashreechowdhury
1

Given:

Mr Chaudhary invests,

Rs 20,800 in 6% Rs 100 shares at Rs 104

Rs 14,300 in 10.5% Rs 100 shares at Rs 143.

To find:

Mr. Chaudhary's annual income from the shares

Solution:

We will first find the individual income from his each investments and then take the sum of both of them to get his annual income from the shares.

Finding the income from the investment of Rs. 20800 in 6%, Rs. 100 shares at Rs. 104:

No. of shares = \frac{[Total\:Investment]}{[Market\:Value\:of\:1\:share]} = \frac{20800}{104} = 200

Income obtained per share = \frac{6}{100} × 100 = Rs. 6

∴ Income obtained from 200 shares = 200 × Rs. 6 = Rs. 1200

Finding the income from the investment of Rs. 14300 in 10.5%, Rs. 100 shares at Rs. 143:

No. of shares = \frac{[Total\:Investment]}{[Market\:Value\:of\:1\:share]} = \frac{14300}{143} = 100

Income obtained per share = \frac{10.5}{100} × 100 = Rs. 10.5

∴ Income obtained from 100 shares = 100 × Rs. 10.5 = Rs. 1050

Finding the annual income from the shares:

Therefore,

The annual income obtained from the shares will be,

= [Income obtained from 200 shares] + [Income obtained from 100 shares]

= Rs. 1200 + Rs. 1050

= Rs. 2250

Thus, his annual income from the shares will be Rs. 2250.

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Answered by lohitha42
0

Answer:

sol. 2250 is the answer

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