Mr. Chopra wants his nameplate to be in the shape of a triangle of sides 37 cm 44 cm
and 49 cm respectively. If the metal sheet is available @ Rs.600 per m2 and the painter
charges @Rs. 250 per m2. Calculate the total cost of his nameplate.
Answers
Answer:
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Solution :-
→ Semi - perimeter of ∆ = s = (37 + 44 + 49)/2 = 130/2 = 65
So,
→ Area of ∆ = √[s * (s - a) * (s - b) * (s - c)]
putting a = 37 , b = 44 , c = 49
→ Area of ∆ = √[65 * (65 - 37) * (65 - 44) * (65 - 49)]
→ Area of ∆ = √(65 * 28 * 21 * 16)
→ Area of ∆ = √(65 * 7 * 4 * 3 * 7 * 16)
→ Area of ∆ = 7 * 8 * √(65 * 3)
→ Area of ∆ = 56√195
→ Area of ∆ ≈ 781.76 cm²
now,
→ Total cost of metal sheet = 781.76 * 600 = Rs.469056
and,
→ Total cost of metal sheet = 781.76 * 250 = Rs.195440
therefore,
→ Total cost of his nameplate = 469056 + 195440 = Rs. 664496 (Ans.)
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