Mr dubey borrows rs 100000 from state bank of india at 11% per annum compound interest he repays 41000 at end of first year
Answers
The amount outstanding at the beginning of the third year is Rs. 30000.
Explanation:
The complete question:
Mr. Dubey borrows Rs.100000 from state bank of India at 11 % p.a compound interest. He repays Rs. 41000 at the end of the first year and RS 47700 at the end of second year. Find the amount outstanding at the beginning of the third year.
Given,
Principle (P) = Rs.100000 and rate (r) = 11 % compounded annualy
Interest after first year =
= Rs. 11, 000
Total amount after 1 year = Rs.100000 + Rs. 11, 000
= Rs. 111,000
Total outstanding after 2 years = Rs. 111,000 - Rs. 41000
= Rs. 70000
Interest after second year =
= Rs. 7700
Total amount after 2 years = Rs. 70000 + Rs. 7700
= Rs. 77700
Total outstanding after 3 years = Rs. 77700 - Rs. 47700
= Rs. 30000
Thus, the amount outstanding at the beginning of the third year is Rs. 30000.
The amount outstanding at the beginning of the third year is Rs. 30000
Complete question:
Mr. Dubey borrows Rs. 100000 from state bank of India at 11% p.a compound interest. He repays Rs. 41000 at the end of the first year and Rs. 47700 at the end of second year. Find the amount outstanding at the beginning of the third year.
Answer:
Given:
Principal = Rs. 100000
Compound interest = 11% p.a
To find:
Amount outstanding at the beginning of the third year = ?
Solution:
The interest after first year is calculated with simple interest formula.
Now, the interest for first year is:
Now, the total money to be paid after 1 year is:
Rs. 100000 + Rs. 11000 = Rs. 111000
From question, Rs. 41000 is repaid.
So, the balance money need to be paid is:
Rs. 111000 - Rs. 41000 = Rs. 70000
Now, the interest for second year is:
So, the total money to be paid after 2 years is:
Rs. 70000 + Rs. 7700 = Rs. 77700
From question, Rs. 47700 is repaid.
So, the balance money need to be paid is:
Rs. 77700 - Rs. 47700 = Rs. 30000