Question

Mr Dubey borrows rupees 100000 from State Bank of India at 11% per annum compound interest he repairs rupees 41000the end of first year and Rupees 47700 at the end of the second year find the amount outstanding and the beginning of the third year​

Answer 1

Answer:

Step-by-step explanation:

Amount  at the end of 2nd year=P(1+R/100)^2

=100000(1+11/100)^2

=100000(111/100)^2

=100000 x (111/100) x (111/100)

=123210 rupees

Total amount paid by Mr Dubey =41000+47700

=88700 rupees

amount left to be paid = 123210-88700

=34510 rupees