Question

Mr. Grover is three times as old as his son and the sum of their ages is 48. How old is each?​

Answer 1

✬ Son = 12 Years ✬

✬ Mr Grover = 36 Years ✬

Step-by-step explanation:

Given:

• Mr Grover is three times as old his son.
• Sum of their ages is 48.

To Find:

• How old is each ?

Solution: Let the age of his son be x years. Therefore,

➯ Mr. Grover age = 3 times of x

➯ Mr Grover age = 3x years

A/q

• Sum of Mr Grover and his son's age is 48 years.

$\implies{\rm }$ 3x + x = 48

$\implies{\rm }$ 4x = 48

$\implies{\rm }$ x = 48/4

$\implies{\rm }$ x = 12

So ages of

• Son's age is 12 years.

• Mr Grover is 3(12) = 36 Years.

[ Verification ]

➮ Mr Grover is 3 times of his son's age.

➮ 36 = 3(12)

➮ 36 = 36

Sum of their ages is 48.

➮ Grover + Son = 48

➮ 36 + 12 = 48

➮ 48 = 48

$\large\bold{\texttt {Verified }}$

Answer 2

Given :-

• Mr. Grover is three times as old as his son.

• The sum of their ages is 48.

To Find :-

• Age Of Both.

Solution :-

Let,

The Age Of Son = x.

The Age Of Mr. Grover = 3x.

According To The Question, The Equation :-

3x + x = 48.

➝ 4x = 48.

➝ x = 48/4.

➝ x = 12.

Now,

• Age Of Son = x = 12.

• Age Of Mr. Grover = 3x = 36.