Math, asked by gudiya10jain, 2 months ago

mr.gupta divides Rupees 81,000 among his three children Ashok, mohit and geeta in such a way ashok gets 4 times what mohit gets and mohit gets 2-5 times what geeta gets. find the share of each of them​

Answers

Answered by sofiaparveen253
1

Answer:

Finally for Ashok, it is given that he gets four times what Mohit gets. Therefore, the share of ashok is: 4×2.5x=10x Rupees. We know that the total of everyone's share will be 81000 Rupees. Thus, Geeta gets 6000 Rupees.

Answered by 6858
0

Answer:

Let the share of Geeta = 1

Share of Mohit is (2-5 times of Geeta) = 2:5

Share of Ashok is (4 times of Mohit) = 4 x 2.5 = 10

Ratio = 1:2.5 :10 = 1 x 2.5 x 2 : 10 x 2 = 2.5 : 20

Sum of ratio = 2 + 5 + 20 = 27

Share of Geeta = \frac{2}{27}\times81000=2\times3000=Rs.6000

27

2

×81000=2×3000=Rs.6000

Share of Mohit = \frac{5}{27}\times81000=5\times3000=Rs.15000

27

5

×81000=5×3000=Rs.15000

Share of Ashok = \frac{20}{27}\times81000=20\times3000=Rs.60000

27

20

×81000=20×3000=Rs.60000

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