Mr. Gupta opened a recurring deposit account in a
bank. He deposited 2500 per month for two years
At the time of maturity he got * 67,500.
Find : (i) the total interest earned by Mr. Gupta,
(ii) the rate of interest per annum.
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given that
Amount deposited by Mr. Gupta per month = ₹ 2500
Period (x) = 2 years = 24 months
Amount got at the time of maturity = ₹ 67500
We know that
Total principal for one month = 2500 × [x (x + 1)]/ 2
Substituting the value of x
= 2500 × (24 × 25)/ 2
By further calculation
= ₹ 750000
Interest = Maturity value – x × deposit per month
Substituting the values
= 67500 – 24 × 2500
= 67500 – 60000
= ₹ 7500
We know that
Period = 1 month = 1/12 year
So the rate of interest = (SI × 100)/ (P × T)
Substituting the values
= (7500 × 100 × 12)/ (750000 × 1)
= 12%
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