Mr. Hart owns a model train store. He uses magnets from The Gadget Factory for the train tracks. Part A The table shows the relationship between the number of train tracks, t, and the number of magnets needed, m. Describe the relationship between the number of tracks and the number of magnets needed. Then write an equation that models this relationship. Number of magnet for 1 train track are 5, Number of magnet for 2 train tracks are 8, Number of magnet for 3 train tracks are 11, Number of magnet for 4 train tracks are 14, Number of magnet for 5 train tracks are 17
Answers
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Grade 7
Mathematics
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Chapters in NCERT Solutions - Mathematics, Class 7
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Exercises in Comparing Quantities
Question 6
Q6) Juhi sells a washing machine for Rs. 13500. She loses 20% in the bargain. What was the price at which she bought it?
Solution:
The selling price of washing machine = Rs. 13500
Loss percent = 20%
Let the cost price of the washing machine be Rs. x.
Loss = Loss% of C.P.
\Rightarrow⇒ Loss = 20% of Rs. x=\frac{20}{100}\times x=\frac{x}{5}x=
100
20
×x=
5
x
Therefore, S.P. = C.P. - Loss
\Rightarrow\ 13500=x-\frac{x}{5}\Rightarrow13500=\frac{4x}{5}⇒ 13500=x−
5
x
⇒13500=
5
4x
\Rightarrow\ x=\ \frac{13500\times5}{4}=\ Rs.\ 16,875⇒ x=
4
13500×5
= Rs. 16,875
Hence, the cost price of washing machine is Rs. 16,875.
Answer:
Question 6
Q6) Juhi sells a washing machine for Rs. 13500. She loses 20% in the bargain. What was the price at which she bought it?
Solution:
The selling price of washing machine = Rs. 13500
Loss percent = 20%
Let the cost price of the washing machine be Rs. x.
Loss = Loss% of C.P.
\Rightarrow⇒ Loss = 20% of Rs. x=\frac{20}{100}\times x=\frac{x}{5}x=
100
20
×x=
5
x
Therefore, S.P. = C.P. - Loss
\Rightarrow\ 13500=x-\frac{x}{5}\Rightarrow13500=\frac{4x}{5}⇒ 13500=x−
5
x
⇒13500=
5
4x
\Rightarrow\ x=\ \frac{13500\times5}{4}=\ Rs.\ 16,875⇒ x=
4
13500×5
= Rs. 16,875
Hence, the cost price of washing machine is Rs. 16,875.