Question

Mr. Jitendra gets 7827 at the end of 18 months at the rate of 11% per annum in
a recurring deposit account. Then, the monthly installment is​

Answer 1

Step-by-step explanation:

may this will help you.

Answer 2

$Given \: marurity\: value (m.v) = Rs\:7827$

$Let \: monthly \: instalment = Rs\:P$

$Here, n = 18 \:months$

$Rate \: of \: interest (r) = 11\% \: p.a$

$m.v = \frac{n(n+1)}{2\times 12} \times \frac{P\times R}{100} + P \times 12$

$\implies 7827 = \frac{18(18+1)}{2\times 12} \times \frac{P\times 18}{100} \times + P\times 18$

$\implies 7827 = \frac{18 \times 19\times 18P}{2\times 12 \times 18} + 18P$

$\implies 7827 = \frac{27\times9P}{200} + 18P$

$\implies 7827 = 9p\Big(\frac{27}{200} + 2\Big)$

$\implies 7827 = 9p\Big(\frac{27+400}{200} \Big)$

$\implies 7827 = 9p\Big(\frac{427}{200} \Big)$

$\implies \frac{7827 \times 200}{9 \times 427 }= P$

$\implies 407.34 = P$

Therefore.,

$\red{ monthly \: instalment} \green { = Rs\:407.34 }$

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