Question

Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents​

Answer 1

Answer:

GOOD MORNING

Let The Cost Price for the first pipe be "x" Dollars

Selling Price = x + 20% of x  

1.20 = x + 20x / 100

1.20 = x + x/5

1.20 = (5x + x)/5

1.20 * 5 = 6x

6 = 6x

x = 1 Dollar

So ,

Cost Price of The Pipe in Which Mr. Jones Got Profit of 20% = 1 Dollar

Let The Cost Price Of The Second Pipe be "y" dollar

Selling Price of second Pipe = y - 20% of y

1.20 = y - 20y/100

1.20 = y - y/5

1.20 = (5y - y)/5

1.20 * 5 =4y

6 = 4y

y = 6/4

y = 3/2

y = 1.5 Dollars  

Total Cost Price Which Mr Jones Paid = 1 + 1.5

                                                                = 2.5 Dollars

Total Selling Price Which Mr Jones Received = 1.2 + 1.2

                                                                            = 2.4 Dollar

Mr. Jones Lost 10 cents

so,

Step-by-step explanation:

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Answer 2

For 1

st

pipes, S.P =1.20 , profit =20 %

C.P=S.P−profit

CP=1.20−20%×CP

∴120% CP=1.20

∴CP=

120

1.20

×100

∴CP

1

=1.00

For 2

nd

=s.p+loss

CP=1.20+200 % CP

∴80% CP=1.20

∴CP=

80

1.20

×100

=1.50

∴ Total CP=1.00+1.50=2.50

Total SP=1.20+1.20=2.40

∴ He suffered 10 paise loss.