Question

Mr Jordan runs a scooter manufacturer factory is factory. His produces 1100 scooters in the third year and the production in the eleventh years is 2700. If the production increases at a steady rate every year, find the production of scooters in 25th year and the total number of scooters
produced in all these 25 years

Answer 1

x+2y =1100
x+10y =2700
by solving y=200 x=500
so that
x+24y = 500 +4800=5300

Answer 2

Answer:

Step-by-step explanatioN

LET 'A' BE THE PRODUCTION FOR FIRST YEAR

'D' BE THE DIFFERENCE IN PRODUCTION EACH YEAR

THEN FOR THE THIRD YEAR = A + 2D = 1100                EQN 1

ELEVENTH YEAR = A + 10D = 2700                                  EQN 2

SUBRTACTING EQN 1 AND 2

8D = 1600

D = 1600/8

= 200

SUBSTITUTING THE VALUE OF 'D' IN EQN 2

A + 10X200 = 2700

A + 2000 = 2700

A = 2700 - 2000

A = 700

THEREFORE THE PRODUCTION IN FIRST YEAR = 700

AP = 700,900,1100..........

25th YEAR = A + 24D

= 700 + 24 X 200

= 5500

AP = 700,900,1100......................5500.

SUM OF SCOOTERS IN 25 YEARS =

S25 = N/2(A + L)

= 25/2(700 + 5500)

=25/2(6200)

=25 X 3100

= 77,500 SCOOTERS

HENCE THE TOTAL PRODUCTION IN 25 YEARS IS 77,500 SCOOTERS.

HOPE THIS HELPS :))