Question

Mr. Kapil Dev. lent some money at 9% and some money at 10% for 2 years.If he had a sum of
4,500 with him, and earned 860, find the amount he invested in each loan.​

Answer 1

AnswEr :

Let the First Part of Sum be Rs. n, and Second Part of Sum be Rs. (4,500 – n).

$\bigstar\:\boxed{\sf Simple\:Interest = \dfrac{Principal \times Rate \times Time}{100}}$

$\rule{120}{1}$

$\underline{\bigstar\:\textsf{According to the Question Now :}}$

$:\implies\sf SI_1 + SI_2 = Total \:Interest\\\\\\:\implies\sf \dfrac{P_1R_1T}{100}+\dfrac{P_2R_2T}{100}=Rs.\:860 \\\\\\:\implies\sf \dfrac{n \times 9 \times 2}{100}+\dfrac{(4500 - n) \times 10 \times 2}{100}=Rs.\:860\\\\\\:\implies\sf \dfrac{18n}{100}+\dfrac{90000 - 20n}{100}=Rs.\:860\\\\\\:\implies\sf \dfrac{18n + 90000 - 20n}{100}=Rs.\:860\\\\\\:\implies\sf90000 - 2n = 860 \times 100\\\\\\:\implies\sf90000 - 2n = 86000\\\\\\:\implies\sf90000 - 86000 = 2n\\\\\\:\implies\sf4000 = 2n\\\\\\:\implies\sf \cancel\dfrac{4000}{2} = n\\\\\\:\implies\sf n = Rs. \:2000$

$\rule{240}{2}$

• E A C H ⠀P A R T S :

↠ First Part = Rs. n = Rs. 2,000

↠ Second Part = Rs. (4,500 - n) = Rs. 2,500

⠀

∴ First Part will be Rs. 2,000 and Second Part will be Rs. 2,500 given on SI.

Answer 2

Question :--- Mr. Kapil Dev. lent some money at 9% and some money at 10% for 2 years. If he had a sum of

4,500 with him, and earned 860, find the amount he invested in each loan.

Solution :---

it is given that total money is Rs.4500 , let he lent Rs.x at 9% and rest Rs.(4500-x) he lent at 10% . Total interest he got from both is given Rs.860 .

we know that,

→ SI = P * R * T /100

Putting all values we get,

→ ( x * 9 * 2 /100) + [(4500-x) * 10 * 2/100 ] = 860

→ (18x/100) + (4500-x)20/100 = 860

→ [ 18x + 90000 - 20x ] /100 = 860

→ 90000 - 86000 = 2x

→ 2x = 4000

→ x = 2000 ..

So, given at 10% = (4500-2000) = Rs.2500..

Hence, Amount given in both 9% and 10% are Rs.2000 and Rs.2500 Respectively...