Math, asked by dotsekekeli14, 9 months ago

Mr.Karikari is five times as old as Eric.In ten years time Mr.Karikari will be thrice as old as Eric. Find their present ages.

Answers

Answered by Anonymous
135

Answer:

Let the Present Age of Eric be n yrs.

Age of Mr. Karikari

↠ Mr. Karikari = Five times of Eric

↠ Mr. Karikari = 5 × n yrs

↠ Mr. Karikari = 5n yrs

____________________

After 10 Years :

⇴ Mr. Karikari = Thrice of Eric

⇴ (5n + 10) = 3 × (n + 10)

⇴ 5n + 10 = 3n + 30

⇴ 5n – 3n = 30 – 10

⇴ 2n = 20

  • Dividing both term by 2

n = 10 yrs

━━━━━━━━━━━━━━━━━━━━━━━━

PRESENT AGES :

⇢ Eric = n = 10 years

⇢ Mr. Karikari = 5n = 5(10) = 50 years

Present Age of Eric and Mr. Karikari is 10 years and 50 years respectively.

Answered by EliteSoul
200

AnswEr:-

Present age of Mr.Karikari = 50 years.

Present age of Eric = 10 years.

Step-by-step-explanation:-

Let present age of Eric be x years & present age of Mr.Karikari be 5x years.

According to question:-

↠ (5x + 10) = 3(x + 10)

↠ 5x + 10 = 3x + 30

↠ 5x - 3x = 30 - 10

↠ 2x = 20

↠ x = 20/2

↠ x = 10 years.

⋆ PRESENT AGES:-

➩ Age of Eric = x = 10 years.

➩ Age of Mr.Karikari= 5x=5(10)= 50 years.

∴ Present ages of Mr.Karikari & Eric are 50 & 10 years respectively.

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