Question

mr. kasam run a small business of making earthen pots . he makes certain number of pots on daily basis. production cost of each pot is 40 Rs more than 10 times total number of pots , he make in one day . if production cost of all pots per day is 600 Rs , find production cost of one pot and number of pot he make per day.

Answer 1

Here is the answer

Let Kasam makes 'x' eathen pots per day .
Then the cost of each earthen pots is Rs.(10x + 40 )

From the given condition,

x(10x + 40) = 600

Therefore,

10x^2 +40x - 600 = 0

Dividing by 10 ,

x^2 + 4x - 60 = 0

x^2 + 10x - 6x - 60 = 0

x(x + 10) - 6(x + 10) = 0

(x - 6)(x + 10) = 0

x = -10 or x = 6

But the number of earthen pots cannot be negative.

So, x = -10 is not acceptable.

So,
x = 6

The cost of each earthen pots
= 10x + 40

= 10(6) + 40

= 60 + 40

= 100

Final answer

He makes 6 earthen pots per day and cost of each earthen pots is Rs 100.

Answer 2

$\textbf{\huge{ANSWER:}}$

Let the number of pots Mr. Kasam makes be = x

Now, we're given that:

Mr. Kasam's production costs Rs.40 more than 10 times the total number of pots.
Equation:
10x + 40

Therefore, $\textbf{ATQ:}$

=》 x(10x + 40) = 600

=》 10x^2 + 40x = 600

=》 10x^2 + 40x - 600 = 0

To simplify the calculation, we can divide the equation by 10:

=》 x^2 + 4x - 60 = 0

=》 x^2 + 10x - 6x - 60 = 0

=》 x ( x + 10 ) - 6 ( x + 10 ) = 0

=》 ( x - 6 ) ( x + 10 ) = 0

=》 x - 6 = 0

=》 x = 6

Put the value of x in the equation, we first formed.

10(6) + 40

=》 60 + 40

=》 100

$\textbf{\huge{100 is the answer.}}$