Mr kasam runs a small business of making earthen pots. he makes certain number of pots on daily basis. production cost of each is rs 40 more than 10 times total number of pots, he makes in one day. if production cost of all pots per day is rs 600,find production cost of one pot and number of pots he makes per day.
Answers
Answered by
0
Step-by-step explanation:
Let no. of pots he makes per day = x
Production cost of each pot is = Rs (40+10x)
cost of all pots per day =600
According to problem ;
Total cost = no. of pots × production cost each pot.
600=x(40+10x)
600=40+10x
2
60=4x+x
2
x
2
+4x−60=0
x=
2
−4±
16+240
x=
2
−4±
256
x=
2
−4+16
,x=
2
−4−16
(not possile)
∴x=6
∴ No. of pots he makes per day = 6
Cost of each pot is = Rs(40+60)=100Rs
Answered by
165
Step-by-step explanation:
Let he makes x pots every day
production value of pot = (10x+40).
As per given equation,
∴ x(10x+40) = 600
∴ 10x² + 40x - 600 = 0
∴ x² + 4x -60 = 0
∴ x² + 10x -6x -60 = 0
∴ x(x+10) -6 (x+10) = 0
∴ (x+10) (x-6) = 0
∴ x+10 = 0 or x-6 = 0
∴ x = -10 or x = 6
x is not equal to -10 because natural number can't be negative.
∴ x = 6
∴ 10x + 40
∴ 10 × 6 + 40
∴ 60 + 40
∴ 100
He makes 6 pots per day and the production value of one pot is 100 rupees.
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