Question

Mr Kasam runs a small business of making earthen pots he makes certain number of pots on daily basis production cost of each pot is 40 more than 10 times total number of pots, he makes in one day. if production cost of all pots per day is rupees 600 find production cost of one pot and number of pots he make per day

Answer 1

Let the number of pots = x
Then the production cost of each pot = 10x + 40
On a particular day the total production cost = 600
That is
The number of pots * The production cost of each pot = The total production cost
x ( 10x + 40 ) = 600
10x^2 +40x - 600 = 0 is a quadratic equation
divide by 10 on both sides
x^2 + 4x - 60 = 0
x^2 + 10x - 6x - 60 = 0
x ( x + 10 ) - 6 ( x + 10 ) = 0
( x + 10 )( x - 6 ) = 0
x = -10 (or) 6
As the number of pots produced can't be negative,
The number of pots produced = 6
Hence, the number of pots produced by the potter on the particular day is 6.

Answer 2

Here is the answer

Let Kasam makes 'x' eathen pots per day .
Then the cost of each earthen pots is Rs.(10x + 40 )

From the given condition,

x(10x + 40) = 600

Therefore,

10x^2 +40x - 600 = 0

Dividing by 10 ,

x^2 + 4x - 60 = 0

x^2 + 10x - 6x - 60 = 0

x(x + 10) - 6(x + 10) = 0

(x - 6)(x + 10) = 0

x = -10 or x = 6

But the number of earthen pots cannot be negative.

So, x = -10 is not acceptable.

So,
x = 6

The cost of each earthen pots
= 10x + 40

= 10(6) + 40

= 60 + 40

= 100

Final answer

He makes 6 earthen pots per day and cost of each earthen pots is Rs 100