Mr. kumar borrowed `15000 for 2 years. The rate of interest for two successive
years are 8% and 10% respectively. Find the outstanding amount at the end of
the second year.
Answers
Answered by
2
Step-by-step explanation:
P = ₹ 15,000
Interest for 1st year
=
15,000×8×1100
= ₹ 1,200
Amount after one year
= ₹ (15,000 + 1,200)
= ₹ 16,200
He repays ₹ 6,200 at the end of the 1st year
∴ Principal for 2nd year
= ₹ (16,200 - 6,200)
= ₹ 10,000
Now interest for the 2nd year
=
10,000×10×1100
= ₹1,000
∴ Amount outstanding at the end of 2nd year
= ₹ (10,000 + 1,000)
= ₹ 11,000.
Answered by
2
Answer:
11000 is right answer......
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