Question

Mr Lalit invested RS 5000 at a certain rate of interest compounded annually of 2 year at the end of first year it amounts to 5325 calculate the rate of interest and the amount at the end of second year to the nearest rupee plz explain​

Answer 1

$\huge\bold\red{Question}$

Mr Lalit invested RS 5000 at a certain rate of interest compounded annually of 2 year at the end of first year it amounts to 5325 calculate the rate of interest and the amount at the end of second year to the nearest rupee plz explain.

$\huge\bold\red{Answer} \:$

$\underline \bold \pink{given} \bold{ \: : \: principal = 5000} \\ \sf{amount \: at \: the \: end \: of \: first \: year = 5325} \\ \boxed{si = amount - principal} \\ si = rs5325 - rs5000 \\ si = rs325 \\ \boxed{rate \: = \: \frac{si \times 100}{p \times t} }\\ \implies \: \frac{325 \times 100}{5000 \times 1} \\ \implies \frac{325}{50} \\ \implies \boxed{6.5\%} \\ \boxed{amount = a \times ( \frac{1 + r}{100 } {)}^{2} } \\ \implies5000( \frac{1 + 6.5}{100} {)}^{2} \\ \implies \frac{5000 \times 1065}{1000} \times \frac{1065}{1000} \\ \implies \frac{1065 \times 1065}{200} \\ \implies213 \times \frac{213}{8} \\ \implies \frac{45399}{8} \\ \boxed{amount \: at \: the \: end \: of \: second \: year = 5671}$

Answer 2

The answer has been calculated approximately......

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