Math, asked by biswadipsarkar6259, 11 months ago

Mr late was 3 times as old as her son 8 yrs ago.Their total agr is 64 now.How old late was

Answers

Answered by hrajm
0
Suppose Mr. late is x years old today.
So his son would be (64- x ) years old.

8 years ago age of Mr. late = x -8 years
and age of his son 8 years ago is = 64-x-8
=56-x years
As 8 years ago Mr late was 3 times than his son.
Hence. (x - 8) =3*( 56 -x )
=> x -8 =168 -3x
=> 4x = 176
=> x =44 years

Mr late is 44 years old in present.

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