Question

Mr Manoj Jindal arranged a lunch party for some of his friends. The expense of the lunch are partly constant and partly proportional to the number of guests. The expenses amount to Rs 650 for 7 guests and Rs 970 for 11 guests .

Denote the constant expense by Rs x and proportional expense per person by Rs y and answer the following questions.
(i) Represent both the situations algebraically.
(a) x + 7y = 650, x + 11y = 970 (b) x - 7y = 650, x - 11y = 970
(c) x+ 11y=650,x+7y=970 (d) 11x + 7y = 650, 11x - 7y = 970

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

Mr Manoj Jindal arranged a lunch party for some of his friends. The expense of the lunch are partly constant and partly proportional to the number of guests. The expenses amount to Rs 650 for 7 guests and Rs 970 for 11 guests .

Denote the constant expense by Rs x and proportional expense per person by Rs y and answer the following questions.

(i) Represent both the situations algebraically.

(a) x + 7y = 650 , x + 11y = 970

(b) x - 7y = 650 , x - 11y = 970

(c) x + 11y = 650 , x + 7y = 970

(d) 11x + 7y = 650 , 11x - 7y = 970

EVALUATION

Here it is given that the constant expense by Rs x and proportional expense per person by Rs y

In first case expenses amount to Rs 650 for 7 guests

So the equation is

x + 7y = 650

In second case expenses amount to Rs 970 for 11 guests

So the equation is

x + 11y = 970

Hence the required system of equations are

x + 7y = 650 , x + 11y = 970

FINAL ANSWER

Hence the correct option is

(a) x + 7y = 650 , x + 11y = 970

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Answer 2

Answer:

option a. x+7y=650 and x+11y=970