Question

mr.mehra gave one-third of his money to his son, one fifth of his daughter, and the remaining amount to his wife. if his wife got rupees 91000, how much money did Mr.mehra have originally.

Answer 1

If Mr. Mehra gave 1/3 and 1/5 of the total to his son and daughter, and the rest to his wife, we can understand that Mrs. Mehra got 8/15th of Mr. Mehra's total money. (∵ 1/3 + 1/5 = 8/15)

We can understand from this that Rs 91000 is 8/15 of the total Mr. Mehra had, which we are going to start calling $x$.

So, $x\frac{8}{15} = 91000$.

Which in turn means $\frac{8x}{15} = 91000$. Now, we can use Algebra to solve for $x$.

[tex]\frac{8x}{15} = 91000 \\\\ 8x = 91000(15) \\ 8x = 1365000 \\\\ x = \frac{1365000}{8} \\ x = 170625[/tex]

Therefore, Mr. Mehra had Rs 1,70,625 in total. at the beginning.

CHECK:

$170625(\frac{8}{15}) = 91000$

hence proved.

Ans: Rs 1,70,625

Answer 2

Answer:

1,95,000

Step-by-step explanation:

Let Mr.Mehra has money=1

Money given to his son=31

and money given to his daughter=51

∴Remaining money given to his wife=1−(31+51)

=1−155+3

=1515−8=157

∴157 of his money=Rs.91,000

∴Total money=Rs.791,000×15

=Rs.13,000×15=Rs.1,95,000