Question

Mr. Mole's burrow lies 5 meters below the ground. He started digging his way deeper into the ground, descending 3 meters each minute.
GRAPH the relationship between Mr. Mole's elevation relative to the ground (in meters) and time (in minutes).

Answer 1

Answer:

See the graph attached

Step-by-step explanation:

Every minute = 3m

At time zero, the depth is zero

Giving coordinates of (0, 0)

At time 1 minute, the depth is 3m

Giving coordinates of (1, 3)

This gives a linear equation

Slope = Δy/Δx

= (3-0)/(1-0)

= 3/1

= 3

Take any general point (x, y)

The equation of the line is:

(y-0)/(x-0) = 3

y/x = 3

y = 3x

See the plot which goes up to a depth of 5m

Answer 2

Given :

Mr. Mole's burrow lies 5 meters below the ground. He started digging his way deeper into the ground, descending 3 meters each minute.

To Find :

GRAPH the relationship between Mr. Mole's elevation relative to the ground (in meters) and time (in minutes).

Solution:

We are given that Mr. Mole's burrow lies 5 meters below the ground.

So, initial position = -5 meters

Slope is the rate of change per unit

We are given that He started digging his way deeper into the ground, descending 3 meters each minute.

So, The slope will be -3 m/min

Since we are given that He started digging his way deeper into the ground So, slope must be negative

General equation : y=mx+c

So, m = -3

c = -5

So, equation : y=-3x-5

y = distance in meters

x = time in minutes

Refer the attached graph

Hence the relationship between Mr. Mole's elevation relative to the ground (in meters) and time (in minutes) is $y=-3x-5$